How Does Beam Sag Affect Belt Tension in Metric Units?

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SUMMARY

The discussion focuses on calculating the force exerted on a belt due to beam sag under a load of 36 lbs (16.33 kg or 160 Newtons). The beam extends 22 inches (0.56 m) from a pivot point, with a sag of 7 degrees. The setup includes two pulleys, one positioned 4.5 inches (0.11 m) above the beam, and the other 4 inches (0.10 m) out from the wall. The calculations are performed using metric units to determine the tension in the belt.

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anyways, there's a beam w/ a weight on the end. total=36 lbs. Its 22 in. out from a pivot on the wall. 4" out from the wall and 1 7/16" up from the beam there's a 4.5" pully. There's also another pully above that, and a belt between those two. The beam sags 7 deg. from wall to tip under load. How much force on the belt?
 

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Please International system, please!
 
metric

36 lbs =16.33 kg / 160 Newtons force down

22 IN = .56m
18 IN = .46m
4 in = .10m
1 7/16 = .037m
4.5 in = .11m
 

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