Trig - Help with tan(arccos(x/3))

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The discussion focuses on calculating tan(arccos(x/3)) using trigonometric identities. The user is advised to draw a right triangle where arccos(x/3) equals theta, establishing that cos(theta) = x/3. By applying the Pythagorean theorem, the sine of theta can be derived, leading to the conclusion that tan(theta) equals sin(theta)/cos(theta). This method effectively utilizes fundamental trigonometric relationships to solve the problem.

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  • Understanding of trigonometric functions, specifically arccosine and tangent.
  • Familiarity with the Pythagorean theorem.
  • Knowledge of right triangle properties.
  • Basic algebra skills for manipulating equations.
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  • Study the derivation of trigonometric identities, particularly for sine and cosine.
  • Learn about the unit circle and its application in trigonometric functions.
  • Explore advanced trigonometric equations and their solutions.
  • Practice problems involving arccosine and tangent to reinforce understanding.
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TKDKicker89
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Can anyone help asap?

tan(arccos x/3)

THanks
 
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Draw a right triangle. If arccos x/3 = theta, draw that triangle.
 
if [tex]\theta=cos^{-1} \frac{x}{3}[/tex]

then [tex]\frac{x}{3}[/tex] is the cosine of [tex]\theta[/tex]

You can use the pythagorean theorem to find the sine of [tex]\theta[/tex]

[tex]\cos^2 \theta + \sin^2 \theta = 1[/tex]

The tangent of [tex]\theta[/tex] is [tex]\frac{sin \theta}{cos \theta}[/tex]
 

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