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eljose
Jul11-05, 11:58 AM
let,s suppose we have the equality:

f(x)g(x)=H(x) now we have that f(x) and H(x) have no Mellin transform..then would be fair to do this?..

f(x)=\frac{1}{2i\pi}\int_{c-i\infty}^{c+i\infty}t^{-s}\frac{M[H(x)]}{M[g(x)]}ds

eljose
Jul11-05, 02:39 PM
Another question..does the Mellin transform of ln\zeta(as) exist? where a >0 and real

and the transform of some of derivatives of ln\zeta(as) ?

eljose
Jul12-05, 04:26 AM
another question let be the integral:

M(s)=\int_0^{\infty}f(t)t^{s-1} then we take the derivative respecto to s

dM(s)/ds=\int_0^{\infty}ln(t)f(t)t^{s-1} so then if dM(s)/ds=r(s) then:

M(s)=\int_s^{\infty}r(p)dp is that correct?..thanx