How Do You Plot the Graph of a Function with Given Derivatives and Asymptotes?

[punjabi_monster]

help please...graph

Here is a question i am havin a bit of trouble with.

http://img125.imageshack.us/img125/8824/cs2rr.jpg

This is what i figured out:

f'(1) must be a local max or min since hte derivativee is 0

the second line are the vertical and horz assympotes.
there is a vertical assymptote at x=0
there is a horizontal assymptote at y=-4 and y=-1

f(-2) is the point where changes concavity

concave down -2<x<0
Concave up x<-2 or x>0


I am unsure of how to draw this graph. thanks for your help in advance.

 

[mathmike]

Yu Just Gave All The Conditions For The Graph. Take A Min Athink About It. First Draw Your Assmytopes, Then Insert Your Critical Points And So On

 

[punjabi_monster]

here is what i get for the graph. can someone please verify it.

http://img77.imageshack.us/img77/7238/graph7zp.jpg

 

[bengalibabu]

that looks about right, i matched up the data given and ur graph...and seems kinda accurate...one thing is that...ur f(-2) doesn't seem to be a point of inflection in ur graph its just going up... without changing direction or anything...so i think u might want to fix that

 

[punjabi_monster]

that looks about right, i matched up the data given and ur graph...and seems kinda accurate...one thing is that...ur f(-2) doesn't seem to be a point of inflection in ur graph its just going up... without changing direction or anything...so i think u might want to fix that

What are you trying to say here bengali babu? i don't understand how you say it seems kinda accurate and then you say that my graph just goes up wihtout changing direction. thank for ur help, but i don't get what ur trying to say. can you please clarify. thanks.

 

[bengalibabu]

actually, i am unsure of this...there might be more to this than i originally thought...maybe someone else cud help u, good luck

 

[punjabi_monster]

thanks anyways bengali , hopefully someone else will be ablle to help me out.