Deriving Kinematics Formula: Step-by-Step Guide with Explanation

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Homework Help Overview

The discussion revolves around deriving the kinematics formula d = 1/2(g)(t^2), which relates distance, gravitational acceleration, and time. The original poster seeks guidance on how to approach this derivation and expresses uncertainty about the foundational concepts involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need for a step-by-step derivation and question the original poster's familiarity with calculus concepts such as derivatives and integrals. There are suggestions to refer to online resources for understanding constant acceleration and the implications of initial velocity in the context of the formula.

Discussion Status

The discussion is ongoing, with participants providing links to resources and attempting to clarify the relationship between initial conditions and the formula. There is a recognition that a solid understanding of basic calculus may be necessary for a deeper exploration of the derivation.

Contextual Notes

The original poster indicates a lack of familiarity with precalculus, which may limit their ability to engage with the mathematical aspects of the derivation. This context suggests that foundational knowledge is a critical factor in the discussion.

Omar.Castillo
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Ok guys I have a genius for a teacher and I want to get this assignment right. This is what he left me Also d = 1/2(g)(t^2)
Using the web resources, find out how to derive that last formula. Write down
the derivation line by line and provide your own comments next to each line.
If you can clarify to yourself why that formula is valid, you will have made a
significant step in understanding some basic physics.

I'll be looking for that derivation in you next email...

But I have no idea where to derive it from any basic formulas or Ideas will truly be helpful. Thanks guys
 
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are you familiar with derivatives and integrals?
 
No man that's what's wrong i barely took precalculus!
 
OK. Look here to see if this helps:
http://hyperphysics.phy-astr.gsu.edu/hbase/imgmec/moteq4.gif

Look at eq.#3. If you imply that the object is DROPPED and not thrown down, that means that Vo = 0. It has no initial velocity. So equation #3 reduces to what you have. If you want to go into the derivation of the previous equations of motion, you will probably be better served by some basic calculus.
 

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