Solving a Problem: Find Mass of Box, Given Two Wire Support Beam Data

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Homework Help Overview

The discussion revolves around a physics problem involving static equilibrium, where two wires support a beam with a box hanging from it. The problem provides specific measurements, including the lengths and tensions in the support wires, and asks for the mass of the box.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the problem, including the positions of the wires and the approach to equilibrium equations. There is an inquiry about the mass of the beam and whether it is uniform, as well as the vertical orientation of the support wires.

Discussion Status

The original poster initially struggled with the problem but later indicated they found the answer independently. Other participants confirmed that the conditions of the problem were appropriate for setting up equilibrium equations, suggesting a productive direction in the discussion.

Contextual Notes

There is a lack of information regarding the mass of the beam, which could influence the analysis. The original poster's previous difficulty with the problem is noted, as well as the urgency due to an upcoming test.

pkossak
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I really could use help on this one! I got this one wrong on the last test, it was driving me crazy. Spent almost half the time trying to figure it out.

Two wires support a beam of length L=16. A box hangs from a wire which is connected a distance of 12 m from the left edge of the beam. The tension in the left support wire is 500 N and the tension in the right support wire is 600 N. What is the mass of the box? DATA: acceleration of gravity=9.80 m/s2

My next test is today, thank you incredibly much if you can help me figure out what I was doing wrong here.
 
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Tell us what you did. (Are you given the mass of the beam? Is it uniform? Are the support wires vertical?)
 
Not given the mass of the beam, yes the support wires are vertical.

The figure can be seen here http://www.msu.edu/~kossakze/physics.gif

The way I approached it was to consider the middle of the beam at m = 0. The left wire is at 8 m and 8 m*500 N + 4 m*x N (weight of box) = 8 m*600 N

nevermind...wow...got the answer, guess I didn't do that on the test.

Thanks anyway
 
Good. As long as the wires are vertical and beam is uniform, no problem. Just set up your equations for equilibrium.
 

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