Proving Energy-Momentum Tesor Relation

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SUMMARY

The energy-momentum tensor for any classical field theory is definitively expressed as -2 times the functional derivative of the action with respect to the metric tensor. This relationship holds true for an action defined as S = SG + SM, where SG represents the gravitational action and SM denotes the matter action. The derivation of the covariant energy-momentum tensor can be achieved by taking the functional derivative of the "free" matter action with respect to the metric tensor, yielding a symmetric tensor that encapsulates the dynamics of matter fields independent of gravitational influences.

PREREQUISITES
  • Understanding of classical field theory concepts
  • Familiarity with the action principle in physics
  • Knowledge of functional derivatives
  • Basic principles of General Relativity (GR)
NEXT STEPS
  • Study the derivation of the energy-momentum tensor from the action principle
  • Explore functional derivatives in the context of field theories
  • Investigate the implications of the energy-momentum tensor in General Relativity
  • Examine examples of "free" matter field Lagrangians and their corresponding energy-momentum tensors
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The discussion is beneficial for theoretical physicists, graduate students in physics, and researchers focusing on classical field theories and their applications in General Relativity.

samalkhaiat
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How can you go about and prove the following :
The energy-momentum tensor for any classical field theory = -2 X the functional derivative of the action with respect to the metric tensor.
 
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Basically, if you have an action for matter interacting with gravity S = SG + SM and perform the functional derivative of S with respect to the metric tensor, you will get a first part corresponding to SG, which will be Einstein’s equations in vacuum, and a second part corresponding to SM, which will be the source of gravity. This is the covariant energy momentum tensor.
 
You are right, this is how textbooks "define" the mater field E-M tensor in GR. This was not what I asked. I wanted a proof for the following;
given any "free" matter field Lagrangian, show that the symmetric E-M tensor is equal to -2 X the functional derivative of the "free" matter action with respect to the metric tensor.(I am asking for proof with no reference to gravity). thanks.
 

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