marioland
Nov8-03, 02:25 PM
Kc = .090
a). Calculate the concn. of all species at equilibrium if 1.00g of water and 4.78g of ClO are mixed in a 1.0L flask.
b). Calculate the concn. of all species at equilibrium if 1.0 mol of pure HOCl is placed in a 2.0L flask. Hint: consider what is now the reactant.
H2O + Cl2O --> 2HOCl
I| 18mol 88 mol 0
C| -x -x +x
E| 18-x 88-x x
Kc= .090 = [HOCl]2 / [H2O].[Cl2O] = x2/(18-x)(88-x)
Solve for x and find all species.Is this the correct way ? Am I confusing you... *hmmm*
a). Calculate the concn. of all species at equilibrium if 1.00g of water and 4.78g of ClO are mixed in a 1.0L flask.
b). Calculate the concn. of all species at equilibrium if 1.0 mol of pure HOCl is placed in a 2.0L flask. Hint: consider what is now the reactant.
H2O + Cl2O --> 2HOCl
I| 18mol 88 mol 0
C| -x -x +x
E| 18-x 88-x x
Kc= .090 = [HOCl]2 / [H2O].[Cl2O] = x2/(18-x)(88-x)
Solve for x and find all species.Is this the correct way ? Am I confusing you... *hmmm*