What Is the Average Acceleration of an Arrow Shot from a Bow?

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Homework Help Overview

The discussion revolves around calculating the average acceleration of an arrow shot from a bow, given its final speed and the distance over which it was accelerated. The subject area includes kinematics and dynamics in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations and question the assumptions regarding initial speed and time. There is exploration of the relationship between average acceleration, change in velocity, and time.

Discussion Status

Some participants have provided hints and guidance regarding the assumptions needed for the calculations. There is an ongoing exploration of different approaches to the problem, with no explicit consensus reached on the final answer.

Contextual Notes

Participants are considering assumptions such as the initial speed of the arrow and the time duration of the acceleration, which may not have been clearly defined in the original problem statement.

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An arrow while being shot from a bow was accelerated over a distance of 2.0 ft. If its speed at the moment it left the bow was 200 ft/sec what was the average acceleration imparted by the bow? Justify any assumptions you need to make.

Ok so I know [itex]v_{0} = 200 \frac{ft}{sec}[/itex]. Also [itex]t = \frac{1}{100}[/itex] second. So would I use the equation [itex]x = x_{0}+v_{x}_{0}t + \frac{1}{2}a_{x}t^{2}[/itex]? Or [itex]2 = v_{x}_{0}t + \frac{1}{2}a_{x}t^{2}[/itex] or [itex]2 = 2 + \frac{1}{2}a_{x}(\frac{1}{100})^{2}[/itex]? I don't think this makes any sense. Maybe I need to make some assumptions?

Thanks
 
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Average acceleration is just change in velocity over change in time. You already have everything you need, but I'll give you a hint with your assumption: What's your starting speed?
 
Indeed, [itex]\overline a = \frac{v_{2}-v_{1}}{t_{2}-t_{1}} = \frac{\Delta v}{\Delta t}[/itex]. So I assume that the starting speed is 0. So we have [itex]\frac{200}{\frac{1}{100}} = 20,000 \frac{ft}{sec^{2}}[/itex]. Is this correct?
 
Yup, no need for messy position formulas. If you really want to test your knowledge of concepts(and if you've covered this material yet), what's the average force exerted by bow onto the arrow? What's the work done by the arrow? Where does the arrow land, and how long is it in flight?
 

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