How Do You Calculate the Direction of a Child Walking on a Moving Ship?

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The discussion focuses on calculating the speed and direction of a child walking on a moving ship. The child walks due east at 1 mile per hour while the ship moves north at 1 mile per hour. The child's speed relative to the water is determined to be approximately 1.41 miles per hour at a 45-degree angle from the north. This is derived from vector addition, where the child's eastward and northward components are both 1 mile per hour, forming a right triangle.

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A child walks due east on the deck of a ship at 1 miles per hour.
The ship is moving north at a speed of 1 miles per hour.

Find the speed and direction of the child relative to the surface of the water.


speed = sqrt(2)

im having trouble finding the direction

The angle of the direction from the north = _____ (radians)

[tex]V_c = <1,0>[/tex]
[tex]V_s = <0,1>[/tex]
[tex]V= <0,V>[/tex]

im not sure how i can find the direction
 
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The reasoning is as follow: The ship's speed is 1mph NORTH relative to water. The child's speed is 1mph EAST relative to the ship. But the ship has eastward speed 0mph. So the child's eastward speed relative to water is 1+0=1mph. Similarily, the child's northward speed relative to water is 0+1mph = 1 mph

So he has an eastward component of 1 and a northward component of 1. Hence is vector speed is <1,1>. Draw this vector and its components. You got yourself a right triangle for which you know 1 angle and 3 sides. It's easy to find the angle giving the direction of the vector speed.
 

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