Write f as piecewise defined function

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Homework Help Overview

The discussion revolves around defining the function f(x) = x + |x| as a piecewise function. Participants are exploring how to express this function based on the behavior of x in different intervals.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants suggest specific piecewise definitions for f(x) based on the sign of x, noting that f(x) simplifies to different expressions for positive and negative values of x. Others question whether to include the case for x = 0 in the definition.

Discussion Status

The discussion is active, with participants providing various interpretations of the piecewise definition. There is acknowledgment of the need to clarify the definition at x = 0, and some guidance has been offered regarding the derivative of the function.

Contextual Notes

Participants mention the importance of correctly defining the function at x = 0 and the implications of the derivative's existence at that point. There are references to previous experiences with grading related to notation in derivatives.

ludi_srbin
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Let f(x)=x+|x| and g be defined by the rule "g(x) is the slope of the graph pf f at x".

Write f as piecewise defined function. :confused:
 
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Can I write it just like

f(x)={ x+|x| if x>1
 
Where x > 0, you get f(x) = 2x.
Where x < 0, you get f(x) = 0.

Does that help?
 
O, got you. Thanks.
 
TD said:
Where x > 0, you get f(x) = 2x.
Where x < 0, you get f(x) = 0.

Does that help?
Minor point: don't forget x = 0 in your definition. :smile:
 
So should I put that also?
 
Make the first one [tex]\ge[/tex] then ;o)
 
And If I want to find g I use derivative?
 
Sure, you could do that. Should be quite simple in this case!
 
  • #10
Yeah. Thanks for help.
 
  • #11
Just remember that your derivative doesn't exist at x=0. I've gotten points taken off because I wrote the derivative with less than or equal signs, even though it's supposed to have just a less than sign.
 

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