Solve Perplexing Physics Problems with These Helpful Tips and Examples"

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SUMMARY

The discussion focuses on solving two physics problems involving kinematics and acceleration. The first problem involves a rock thrown upward from a 100 m cliff and requires determining the timing for a second rock dropped from rest to ensure both reach the ground simultaneously. The correct method involves calculating the total time for both rocks to hit the ground, rather than simply using the initial velocity. The second problem pertains to a superball rebounding off a wall, where the average acceleration is calculated using the change in velocity over the contact time of 3.5 ms.

PREREQUISITES
  • Understanding of kinematic equations, specifically v = u + at
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Familiarity with the concept of average acceleration
  • Basic principles of motion and free fall
NEXT STEPS
  • Study the derivation and application of kinematic equations in vertical motion
  • Learn how to calculate the time of flight for objects in free fall
  • Explore the concept of impulse and momentum in collisions
  • Practice problems involving average acceleration and changes in velocity
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Students studying physics, educators teaching kinematics, and anyone looking to improve their problem-solving skills in motion-related topics.

Pseudo Statistic
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Hi.
I'm having problems with some Physics problems; among them:

9. At the top of a cliff a 100 m high, a rock is thrown upward with velocity 15 m/s. How much later should a second rock be dropped from rest so both stones arrive simultaneously at the bottom of the cliff?

a. 5.05 s

b. 3.76 s

c. 2.67 s

d. 1.78 s

2. A 50-gram superball traveling at 25 m/s is bounced off a brick wall and rebounds at 22 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 3.5 ms, what is the average acceleration of the ball during this time interval?

a. 13,428 m/s2

b. 6,715 m/s2

c. 857 m/s2

d. 20 m/s2

For 9), I thought I'd use v = u + at and find 2t after solving:
0 = 15 - 9.8t for t, and that would give me the answer... but I'm wrong.
Anyone know how I can go about this one?
And for 2), I really don't know what to do...

Thanks for any help.
 
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For the first one, your answer was wrong because the first rock will have a downward speed of 15 m/s when it passes you again, and the other rock is dropped from rest. You need to drop the second rock before this point, and the only way to figure out when is to find the total time it will take each rock to hit the ground.

For the second, acceleration is the change in velocity over time. This problem is easier then it seems.
 

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