Calculating the Height of a Stadium Using Ball Drop: 2.29 Seconds & Speed

Click For Summary

Homework Help Overview

The discussion revolves around calculating the height of a stadium based on the time it takes for a ball to hit the ground after being dropped, specifically focusing on a drop time of 2.29 seconds. Participants explore the physics of free fall, including the equations of motion and the concepts of acceleration due to gravity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the appropriate equations to use for calculating height and final velocity, questioning assumptions about initial speed and the nature of free fall. There are attempts to derive height using the equation for motion under constant acceleration and discussions about the relationship between speed and time.

Discussion Status

The discussion is active with various interpretations being explored. Some participants have provided guidance on using specific equations, while others are questioning the calculations and assumptions made regarding initial conditions and the effects of gravity.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information available for certain scenarios, such as when an object is thrown versus dropped. There are also discussions about the implications of different drop times on height calculations.

thschica
Messages
47
Reaction score
0
A ball is droped from a stadium.It hits the ground 2.29 seconds later.How high is the stadium?Do I use this equation?.5at^2(Thant is wrong isn't it?) How fast is the ball going when it hits the ground?(what equation do I use on this one?)
 
Last edited:
Physics news on Phys.org
I'm assuming no initial speed, then the height h is given by:

[tex]h = h_0 - \frac{{gt^2 }}{2}[/tex]

Here, [itex]h_0[/itex] is the initial height, so what you are looking for. You choose h = 0, because that's where it hits the ground. Then fill in t and g and solve for [itex]h_0[/itex].
 
In this case would the answer be about 25.7 meters? And How do I tell How fast the marble is going?
 
That seems to be correct yes.

For the other question, use a relation between acceleration, speed and time. If time is in s and acceleration in m/s², what would give speed (m/s)?
 
would that equation be the y='s one?
 
I was thinking about v = at
 
I have another question.If something is dropped and hits the ground one second later how high is it? With that equation I got 7.1.Why is it not 9.8 meters?
 
Because it's not the speed which is 9.8m/s but the acceleration which is 9.8m/s².
Are you sure you got 7.1 though?
 
No I got 4.9 sorry
 
  • #10
Would the ball be going 22m/s before it hit the ground?
 
  • #11
thschica said:
No I got 4.9 sorry
That is correct.

You see, an acceleration of 9.8m/s² means that after a full second, the speed has increased 9.8m/s. So when dropping something with no initial speed, it only reaches the speed of 9.8m/s after the full second, so when it hits the ground in your example.

The avarage speed was 9.8/2 = 4.9, exactly what you found :smile:

thschica said:
Would the ball be going 22m/s before it hit the ground?
That seems correct, approximately.
 
  • #12
Thank You so much TD
 
  • #13
No problem :smile:
 
  • #14
Say someone threw the ball up and it didnt hit the ground until 3.53 seconds later how do I find out the ending velocity?What if it was thrown down and hit the ground 1.81 seconds later?
 
  • #15
Thrown up would require the initial height and thrown down the initial speed, unless there is none.

Perhaps someone else can help, I'm logging off. 2.50 AM here, good luck!
 

Similar threads

Replies
7
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
5K
Replies
34
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K