What would be the energy eigenvalues of this particle?

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SUMMARY

The energy eigenvalues for a particle of mass m confined in a three-dimensional box with dimensions L, 2L, and 2L are given by the formula: \(\frac{h^2}{8m}(\frac{n_1^2}{L^2}+\frac{n_2^2}{4L^2}+\frac{n_3^2}{4L^2})\), where \(n_1, n_2, n_3\) are quantum numbers that can take values 1, 2, etc. The initial assumption of energy eigenvalues as hcross*w*A is incorrect. The correct formulation accounts for the specific dimensions of the box and the mass of the particle.

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howdy all,
i need some answers if possible
suppose i have a particle mass m, confinded in a 3d box sides L,2L,2L
what would be the energy eigenvalues of this particle
i presumed it to be:

hcross*w*A
where hcross is h/2*pi
w is omega
and A is the 'amplitude' of the wavefunction.
can someone confirm this or tell what it may actually be
thanks
peace
 
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Your answer is not correct, the correct answer should be.
[tex]\frac{h^2}{8m}(\frac{n_1^2}{L^2}+\frac{n_2^2}{4L^2}+\frac{n_3^2}{4L^2})[/tex],
[tex]n_1=1,2..., n_2, n_3[/tex] are the same.
 
Last edited:
hey thanks heaps for your help brother
peace
 

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