Simple Elevator Ball Physics Problem

[Grandmas]

To many this would be a simple plug it into equation problem. But for some reason this just isn't clicking for me. Here's the problem:

An open elevator is ascending with a constant speed V of 32ft/sec. A ball is thrown straight up by a boy in the elevator when it is a height h of 100 feet above the ground. The initial speed of the ball with repect to the elevator is Vo= 64ft/sec. (A) What is the maximum height attained by the ball? (B) How long does it take for the ball to return to the elevator?

I don't know where to start or what to plug in, please help me out, much appreciated and thanks.
~Grand

 

[snooper007]

(A) $$\frac{64 \times 64}{2G}$$
G is the Newton acceleration constant, in international units, it is $$9.8 meter/sec^2$$.
I don't know how to convert to your unit, ft! you must convert G to ft.
(B) $$\frac{64}{G}$$

 

[Mk]

(A) $$\frac{64 \times 64}{2G}$$
G is the Newton acceleration constant, in international units, it is $$9.8 meter/sec^2$$.
I don't know how to convert to your unit, ft! you must convert G to ft.
(B) $$\frac{64}{G}$$

In physics you should use SI units anyway.