Projectile Problem: Stones Meet at Height

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Homework Help Overview

The problem involves two stones thrown vertically with the same initial velocity, where the first stone is thrown 1 second before the second. The objective is to determine the height at which the two stones meet during their respective trajectories.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations and the timing of the stones' throws. Some express uncertainty about how to initiate the problem, while others suggest focusing on the time difference between the two throws.

Discussion Status

The discussion is ongoing, with some participants providing hints about relevant equations and the relationship between the times of the two stones. There is an acknowledgment of varying levels of understanding among participants.

Contextual Notes

One participant indicates a lack of familiarity with kinematic equations, which may affect their ability to engage with the problem effectively. The problem's setup involves specific timing and initial conditions that are critical to the discussion.

Neerolyte
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Suppose you throw a stone straight up with an initial velocity of 10.5 m/s and, 1.0 s later you throw a second stone straight up with the same initial velocity. The first stone going down will meet the second stone going up. At what height above the point of release do the two stones meet?
 
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What have you tried? Where are you stuck?

You need to know the kinematics equations to answer this problem.

HINT: The time for the second stone is (t-1)
 
hm...basically i need help for the whole question
i have no idea how to even start the question
 
s(t)=-4.9t2+v0t+h

Using this and the previous suggestion, you shouldn't have any trouble.
 

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