Wondering where the distance formula from acceleration due to gravity comes from

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SUMMARY

The distance formula derived from acceleration due to gravity is expressed as d = 1/2 gt². This formula originates from integrating the acceleration due to gravity, represented as a = -g, twice with respect to time. The integration process introduces two arbitrary constants, which are resolved by applying the initial conditions y(0) = 0 and y'(0) = 0. This establishes the relationship between distance, gravitational acceleration, and time in a free-fall scenario.

PREREQUISITES
  • Understanding of basic calculus, specifically integration.
  • Familiarity with the concept of acceleration due to gravity (g).
  • Knowledge of initial value problems in differential equations.
  • Basic physics principles related to motion under constant acceleration.
NEXT STEPS
  • Study the derivation of kinematic equations in physics.
  • Learn about solving initial value problems in differential equations.
  • Explore the implications of gravitational acceleration in different contexts.
  • Investigate the relationship between distance, velocity, and acceleration in motion.
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the mathematical foundations of motion under gravity.

Icedfire01
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Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.
 
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If a=g, then integrate twice with respect to time !
 
That's almost right. When you integrate twice you pick up two arbitrary constants of integration. To really derive the formula you would have to solve the following initial value problem:

[tex]\frac{d^2y}{dt^2}=-g[/tex]

[tex]y(0)=0[/tex]

[tex]y'(0)=0[/tex].
 

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