Finding various derivatives - Help

  • Thread starter Thread starter mousesgr
  • Start date Start date
  • Tags Tags
    Derivatives
Click For Summary

Homework Help Overview

The discussion revolves around finding various derivatives, specifically focusing on functions involving exponential forms, rational expressions, and trigonometric identities. The subject area includes calculus and differentiation techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the differentiation of the function y = x^(a^x) and suggest using logarithmic differentiation. There are attempts to derive patterns for the nth derivatives of rational functions and trigonometric functions. Some participants express familiarity with specific problems while others provide hints and partial methods.

Discussion Status

The conversation includes various approaches to the problems, with some participants offering guidance on how to tackle specific derivatives. There is a mix of attempts to derive solutions and questions about the methods being used, indicating an ongoing exploration of the topics without a clear consensus.

Contextual Notes

Some participants note the need to calculate multiple derivatives to identify patterns, while others question the assumptions behind the methods suggested. There is also mention of homework constraints influencing the discussion.

mousesgr
Messages
31
Reaction score
0
find

1 .derivaive of y, y = x^a^x

2. nth derivaive of (x+p)^-1 p is constant

3. nth derivaive of (ax+b)/(cx+d)

4. nth derivaive of y = sin (^2) x
 
Physics news on Phys.org
Looks like homework to me. Is it?

The first one like you need to work with ln(y)= (a^x)ln x.

The others, just calculate two or three derivatives and see if you can spot a pattern.
 
i know how to do qs 1
 
Did you read what I wrote before?

For [tex]y= x^{(a^x)}[/tex], take the logarithm of both sides:

ln(y)= axln(x). Now differentiate both sides, with respect to x.
(You will need to use the chain rule on the left side and the product rule on the right.)
 
HallsofIvy said:
Did you read what I wrote before?

For [tex]y= x^{(a^x)}[/tex], take the logarithm of both sides:

ln(y)= axln(x). Now differentiate both sides, with respect to x.
(You will need to use the chain rule on the left side and the product rule on the right.)

i mean i know how to do the first one now
 
For #2, you can use: (ab)' = b ab - 1.
Then note that (x + p)' = 1.
For example: [tex]y' = \left( \frac{1}{x + p} \right)' = -\frac{1}{(x + p) ^ 2}[/tex]
[tex]y'' = (y')' = -\left( \frac{1}{(x + p) ^ 2} \right)' = 2\frac{1}{(x + p) ^ 3}[/tex]
So [tex]y ^ {(n)} \ = \ ?[/tex]
-----------------------
For #3, you need to arrange [tex]\frac{ax + b}{cx + d}[/tex] into something like: [tex]C + \frac{A}{cx + d}[/tex], where C, and A = const.
Then you just do the same like #2.
-----------------------
For #4, you can try to take 1st, 2nd, 3rd, 4th, ... derivative of the function and see the rule.
Note that 2sin(x)cos(x) = sin(2x).
Viet Dao,
 
mousesgr said:
find

1 .derivaive of y, y = x^a^x

2. nth derivaive of (x+p)^-1 p is constant

3. nth derivaive of (ax+b)/(cx+d)

4. nth derivaive of y = sin (^2) x

1. ln y = a^x lnx
y'/y = [xa^(x-1)]lnx + [(1/x)a^x]
y' = y[[xa^(x-1)]lnx + [(1/x)a^x]]

2. -1(x+p)^-2
too lazyt to do the rest..
 

Similar threads

  • · Replies 28 ·
Replies
28
Views
1K
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
42
Views
4K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
1
Views
3K
Replies
4
Views
3K