irony of truth
Sep17-05, 07:39 AM
Is there a site which has a "program" that allows me to enter two dates and then the program will compute the length of time between these two dates?
ComputerGeek
Sep17-05, 04:49 PM
why not sit down and figure that out yourself? heck, you could write a perl script to do that/
eNathan
Sep19-05, 05:22 PM
I wrote a function in Delphi that does that. Im not sure if you have Delphi or not. If you really want I can write a VB code and it should be easily transated to VB Script to be used in Web Browsers. By the way, it returns the result in seconds. Here ya go. (may get range check error if Date1 > Date2 ^^)
Function SubtractDateTime(Date1, Date2: TDateTime): Extended;
Const
{-Time-}
Millisecond = 0.001;
Second = 1; Seconds = 1;
Minute = 60; Minutes = 60;
Hour = 3600; Hours = 3600;
Day = 86400; Days = 86400;
Week = 604800; Weeks = 604800;
Month = 2629743.83; Months = 2629743.83;
year = 31556926; years = 31556926;
Decade = 315569260; Decades = 315569260;
Century = 3.1556926 * 10e09;
Millenium = 3.1556926 * 10e10;
{-/Time-}
var
Hour1, Min1, Sec1, MSec1 : Word;
Y1, M1, D1: Word;
Hour2, Min2, Sec2, MSec2 : Word;
Y2, M2, D2: Word;
RHour, RMin, RSec, RMSec, RY, RM, RD: Word;
Begin
Try
Result := 0;
DecodeDate(Date1, Y1, M1, D1);
DecodeDate(Date2, Y2, M2, D2);
DecodeTime(Date1, Hour1, Min1, Sec1, MSec1);
DecodeTime(Date2, Hour2, Min2, Sec2, MSec2);
RHour := Hour1 - Hour2;
RMin := Min1 - Min2;
RSec := Sec1 - Sec2;
RMSec := MSec1 - MSec2;
RY := Y1 - Y2;
RM := M1 - M2;
RD := D1 - D2;
Result := Result + RHour * Hour;
Result := Result + RMin * Minute;
Result := Result + RSec * Seconds;
Result := Result + RMSec * MilliSecond;
Result := Result + RY * Year;
Result := Result + RM * Month;
Result := Result + RD * Day;
Except Result := 0;//wtf ^^
End;
End;
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