At What Temperature Do Copper and Iron Wires Have Equal Resistance?

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Homework Help Overview

The discussion revolves around determining the temperature at which the resistances of copper and iron wires are equal, given their resistances at a specific temperature and their resistivity values.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of formulas related to resistance and temperature coefficients, with one participant suggesting a specific formula for calculating resistance changes with temperature. Another participant provides a detailed breakdown of the calculations involved in finding the temperature where resistances are equal.

Discussion Status

The discussion includes attempts to derive the temperature mathematically, with one participant providing a step-by-step calculation. However, there is a note of potential error regarding the temperature coefficient for iron, prompting further reflection on the accuracy of the calculations presented.

Contextual Notes

Participants are working under the assumption that the relationship between resistance and temperature is linear for pure metals, and there is a need to clarify the correct values for temperature coefficients used in the calculations.

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A copper wire has a resistance of 0.501 ohms at 20.0 degrees C, and an iron wire has a resistance of 0.487 ohms at the same temperature. At what temperature are their resistances equal?

Resistivity of Copper: .0039
Resistivity of Iron: .0005
 
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Try this formula

[tex]\frac{{\Delta R}}{R_0} = \alpha \Delta T[/tex]


You need to look up the alpha
 
For pure metals the relationship is (almost) linear and the formula is:
R=R0[1+[tex]\alpha[/tex](T-T0)

FYI the figures quote are temperature coefficients measured in K-1 (degrees Celsius to the minus one is also fine, as the increments are the same. Just don't mix the two as values for T and T0 in one calculation):

Where you want the resistance to be equal, you just back the copper and iron halves of the equation together (copper on the left, iron on the right).

0.501 [1 + 0.0039 (T - 20)] = 0.487 [1 + 0.0005 (T - 20)]

Multiply the lot out, so as to separate T
0.501 + 0.0019539T - 0.039078 = 0.487 + 0.0002435T - 0.00487

Real numbers on the left, expressions in T on the right
0.501 - 0.487 - 0.039078 + 0.00487 = (0.0002435 - 0.0019539)T
-0.020208 = -0.0017104T

Divide both sides by -0.0017104
T=11.81478017 degrees Celsius

It you subs in [T-20] as -8.185 into either equation to double check, at T, the resistance will be about 0.485[tex]\Omega[/tex]

6 years late, but hope this helps.
 
Last edited:
On reflection, I have noticed that Iron has a resistance temperature coefficient of 0.005K-1, not 0.0005K-1. The principle of working through it is still correct, but this answer is only correct for the question asked incorrectly ...if that makes any sense :smile:
 

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