Solving √ x + 4/3 y with p = 3.4 e3 Kg m-³

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Homework Help Overview

The discussion revolves around a mathematical expression involving square roots and variables, specifically focusing on the equation √(x + (4/3)y) with a given density p. The context includes the need to calculate a result in kilometers per second, with specific values for x, y, and p provided.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are exploring whether the approach involves direct substitution of values into the equation. There is also a discussion about handling units consistently to facilitate conversion to the desired output.

Discussion Status

Some participants have offered guidance regarding unit conversion and the importance of using base units throughout the calculations. The original poster expresses intent to revisit the problem based on the feedback received.

Contextual Notes

There is a mention of uncertainty regarding the proper handling of the square root symbol and the need for clarity in unit conversions, particularly from m/s to km/s.

stepha
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Heres the question – :bugeye:

√ x + 4/3 y
√ p
(this whole equation should be squared, but not sure how to make the square root symbol big enough)

p = 3.4 e3 Kg m-³

x = 1.6 e11 N m-²

y = 6.4 e10 N m-²

I need to calculate the answer and give my answer in Km s-1 (Km per second)

Any ideas?? :confused:
 
Last edited:
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I don't understand... are you just trying to substitute them in?
 
If the problem is with the units, just use base units all the way through (kg, m, s) and then your final answer will be in m/s. Then its easy to convert m/s to km/s.
 
thank you for the advice, I will have another go
 

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