Proving the Laplace Operator in Polar Coordinates

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Homework Help Overview

The discussion revolves around proving a mathematical identity involving the Laplace operator in polar coordinates. The original poster expresses confusion about how to approach the problem, which involves second derivatives of a function U defined in terms of Cartesian coordinates (x, y) and their polar counterparts (ρ, θ).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants suggest using the chain rule to find the necessary derivatives, while others express uncertainty about assumptions regarding the function U. There is a discussion about the complexity of the derivatives and the need for clarification on how to proceed.

Discussion Status

The conversation is ongoing, with participants exploring different approaches to differentiate U in polar coordinates. Some guidance has been offered regarding the use of the chain rule, but there remains a lack of clarity and consensus on the initial steps and assumptions needed for the proof.

Contextual Notes

Participants note the absence of a specific form for U and question whether any assumptions should be made about it, indicating a potential gap in the problem setup.

thenewbosco
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calculus--differentiation Help Please!

if [tex]x=\rho cos \theta[/tex] and [tex]y=\rho sin \theta[/tex]

prove that if U is a twice differentiable function of x and y that
[tex]\frac{\partial^2U}{\partial x^2} + \frac{\partial^2 U}{\partial y^2} = \frac{\partial^2 U}{\partial \rho^2} + \frac{1}{\rho}\frac{\partial U}{\partial \rho} + \frac{1}{\rho^2}\frac{\partial^2 U}{\partial \theta^2}[/tex]

I have absolutely no clue how to get started on this one.

thanks
 
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anyone...
 
Try using the chain rule to find [tex]\frac{\partial U}{\partial\theta}[/tex]. The do it agian to find the second derivatives. Hope it works!
 
I could try this except for the fact that i do not know what U equals...is there some assumption i am supposed to make here
 
No assumption. Just use [tex]\frac{\partial U}{\partial \theta } = \frac{\partial U}{\partial x} \frac{\partial x}{\partial \theta}+ \frac{\partial U}{\partial y} \frac{\partial y}{\partial \theta}[/tex]
 
its messy!
 
i'm sorry i don't quite understand what i am supposed to be doing here. can i get a some explanation as to how and why to start this. i have really no idea here. thanks
 

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