Converting from square to polar coordinants

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SUMMARY

The discussion focuses on converting the equation x² - 2y = 0 into polar coordinates. The correct transformation is r² * cos²(θ) - 2r * sin(θ) = 0. It is confirmed that dividing through by r (assuming r ≠ 0) simplifies the equation to r = 2sin(θ) / cos²(θ). Additionally, the use of θ is preferred over φ in polar coordinates.

PREREQUISITES
  • Understanding of polar coordinates and their notation
  • Familiarity with trigonometric functions (sine and cosine)
  • Basic algebraic manipulation skills
  • Knowledge of Cartesian coordinates and their conversion to polar form
NEXT STEPS
  • Study the derivation of polar coordinates from Cartesian coordinates
  • Learn about the applications of polar coordinates in calculus
  • Explore trigonometric identities and their use in coordinate transformations
  • Investigate the graphical representation of polar equations
USEFUL FOR

Students and educators in mathematics, particularly those studying coordinate systems, algebra, and trigonometry. This discussion is also beneficial for anyone looking to understand the conversion process between Cartesian and polar coordinates.

Bob19
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Hi

If I have the following equation:

x^2 - 2y = 0

I need to convert it into polar coordinants:

r^2 * cos(phi)^2 - 2*r* sin(phi) = 0

Is this correct ?

/Bob
 
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Yes, it is correct.
 
Bob19 said:
Hi

If I have the following equation:

x^2 - 2y = 0

I need to convert it into polar coordinants:

r^2 * cos(phi)^2 - 2*r* sin(phi) = 0

Is this correct ?

/Bob

And, of course, as long as r is not 0, you can divide through by r to get
[tex]r cos^2(\theta)- 2sin(\theta)= 0[/tex]
or
[tex]r= \frac{2sin(\theta)}{cos^2(\theta)}[/tex]

(It is customary to use "theta" in polar coordinates rather than "phi")
 

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