Projectile Motion Lab: Finding Angle for Hitting a Falling Target

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SUMMARY

The discussion focuses on determining the launch angle required for a projectile to hit a falling target in a physics lab. The key variables are the height of the target (h) and the horizontal distance from the launcher to the target (Dx). The user is advised to utilize the kinematic equations, specifically the equation y = vy(t) - 0.5gt², to derive the necessary angle. The projectile follows a parabolic path, while the target falls under gravity, necessitating the setting of their respective y-values equal to each other for accurate calculations.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of projectile motion principles
  • Familiarity with the concepts of vertical and horizontal motion
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of projectile motion equations
  • Learn how to apply kinematic equations to real-world scenarios
  • Explore the effects of varying launch angles on projectile trajectories
  • Investigate the relationship between time of flight and distance in projectile motion
USEFUL FOR

Students in physics courses, educators teaching projectile motion, and anyone conducting experiments related to kinematics and projectile trajectories.

jess2424
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I'm having some difficulty doing this lab, so if anyone could point me in the right direction that would be awesome.

I basically have to determine what angle to set a launcher at so that the projectile will hit a falling target. I have to derive an actual equation. The only measurements I will be able to make is the height of the target (before it falls) and the distance from the launcher to the target.

I've uploaded a crummy diagram of the set-up:


http://img323.imageshack.us/img323/1853/untitled5po.png


Remember, the only variable I'll be able to insert values for is 'h' and 'Dx'. I know that I have to start with the five kinematics equations, but I've reached a dead end.

Has anyone done this lab before? Is anyone able to point me in the right direction?
 
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Hmmm...

Since y=vy(t)-.5gt²
And since both the bullet and target need to meet at the same level, set the two y values equal to each other?

vsinθ-.5g(2vy/g)²=vsin0-5g((2y/g)^1/2)²
The first portion of the equality is the bullet, which follows a Case 2 motion, a parabolic path with an angle and non-zero vy component. The second portion of the equality is the case 1 scenario that the target follows.

try that out, it MIGHT help out. I don't know for sure of course, but it would be the first thing I would try-keep in mind I don't really know the problem, as in, what you need to show or do.
 

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