Calculating Tension in a Sleigh Rope on Snow

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Homework Help Overview

The problem involves calculating the tension in a rope used to pull a sleigh with children over snow, considering the effects of friction and the angle of the rope. The context is rooted in mechanics, specifically focusing on forces acting on the sleigh.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to determine the normal force and its relationship to the gravitational force, noting that it is not equal due to the angle of the rope. Some participants suggest revisiting the free body diagram (FBD) to clarify the components of the forces involved.

Discussion Status

Participants are actively engaging with the problem, offering insights about the forces at play and questioning the assumptions regarding the normal force. There is a focus on understanding the implications of the angle of the rope and its effect on the normal force.

Contextual Notes

The problem includes specific values such as mass, angle, and coefficient of friction, but there is an acknowledgment of missing information regarding the exact calculation of the normal force and the tension in the rope.

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This is the question I am working on:

An adult is pulling two small children in a sleigh over level snow. The sleigh and children have a total mass of 47 kg. The sleigh rope makes an angle of 23 degrees with the horizontal. The coeffcient of friction between the sleigh and the snow is 0.11. Calculate the magnitude of the tension in the rope needed to keep the sleigh moving at a constant velocity. (Hint: The normal force is not equal to the force of gravity.)

I drew a FBD diagram and broke the information down;

m = 47 kg
a = 0
uk = 0.11

Now the way I was going to do it was find normal force, then use that in (FN)(uk ) = Fk to find the kinetic friction.

Then I was going to put Fk = Ft (kinetic friction = tension)

However, I am having difficulting finding the normal force, since it is not equal to force of gravity.

Thanks in advance.

O, and it's my first day here, hello all posters.
 
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Go back to your FBD. The rope pulls on the sleigh at an angle. Therefore, there is a component of rope force in the positive vertical direction. That's why the normal force isn't equal to gravity (it's something less).
 
hotvette said:
Go back to your FBD. The rope pulls on the sleigh at an angle. Therefore, there is a component of rope force in the positive vertical direction. That's why the normal force isn't equal to gravity (it's something less).

You know what, I was pondering that and think it would be ___sin23 but am not sure what would go in the blank.
 
That would be T, the tension in the rope. All you have to do is sum the forces, write F = ma (in the horizontal direction), and go from there. Hint: what can you say about acceleraton if velocity is constant?
 

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