Physics Problem Help: Chin-Up Force & Velocity

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The physics problem involves calculating the velocity of a person performing a chin-up, where the individual exerts a force of 700N and each arm applies an upward force of 355N during the first 25.0 cm of the lift. The relevant equations include the work-energy principle, represented as Kf – Ki + Uf – Ui = Wnc, and the derived expression for final velocity: 1/2mVf - 1/2Vi + mgyf - mgyi = Wnc. A free body diagram is essential for visualizing the forces at play in this scenario.

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I am working on a physics problem which states:
A person doing a chin-up 700N exclusive of the arms. During the first 25.0 cm of the lift, each arm exerts an upward force of 355 N on the torso. If the upward movement starts from resdt, what is the person's velocity at this point?

This is probably very basic, but I am having trouble with this whole energy, work, force, tension thing.
 
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Explain what you've tried and what equations are relevant. Have you drawn a free body diagram and labeled the forces?
 
You should have these formulas, derive an expression for final velocity and then plug in your numbers

Kf – Ki + Uf – Ui = Wnc
1/2mVf-1/2Vi+mgyf-mgyi=Wnc
 

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