dimensionless
Oct5-05, 05:44 PM
I'm trying to figure out this equation.
{\Psi} = Ae^{-a(bx-ct)^2}
I've expanded this to
{\Psi} = Ae^{-ab^2x^2-abxct-ac^2t^2}
When I try to find the derivative I get this
\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }
\pd{\Psi}{t}{}\right)_x = (-2ac^2t-abxc)Ae^{-ab^2x^2-abxct-ac^2t^2}
I should get this instead
\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }
\pd{\Psi}{t}{}\right)_x = (-2abcx-2ac^2t)Ae^{-ab^2x^2-abxct-ac^2t^2}
Can anyone tell me where my error is and how I can fix it?
{\Psi} = Ae^{-a(bx-ct)^2}
I've expanded this to
{\Psi} = Ae^{-ab^2x^2-abxct-ac^2t^2}
When I try to find the derivative I get this
\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }
\pd{\Psi}{t}{}\right)_x = (-2ac^2t-abxc)Ae^{-ab^2x^2-abxct-ac^2t^2}
I should get this instead
\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }
\pd{\Psi}{t}{}\right)_x = (-2abcx-2ac^2t)Ae^{-ab^2x^2-abxct-ac^2t^2}
Can anyone tell me where my error is and how I can fix it?