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dimensionless
Oct5-05, 05:44 PM
I'm trying to figure out this equation.


{\Psi} = Ae^{-a(bx-ct)^2}


I've expanded this to


{\Psi} = Ae^{-ab^2x^2-abxct-ac^2t^2}


When I try to find the derivative I get this


\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }

\pd{\Psi}{t}{}\right)_x = (-2ac^2t-abxc)Ae^{-ab^2x^2-abxct-ac^2t^2}


I should get this instead


\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }

\pd{\Psi}{t}{}\right)_x = (-2abcx-2ac^2t)Ae^{-ab^2x^2-abxct-ac^2t^2}


Can anyone tell me where my error is and how I can fix it?

krab
Oct5-05, 06:25 PM
Try again in expanding
(bx-ct)^2