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tatoo5ma
Oct5-05, 08:28 PM
Hello,
I have to write {\it sina}+{\it sinb}+\sin \left( a+b \right) as a product.
Here is what I began with, then I got stuck...
2\,\sin \left( (a+b)/2 \right) \cos \left( (a-b)/2 \right) +{\it sina}\,{\it cosb}+{\it cosa}\,{\it sinb}

Anyone please can help me out, that would be great, thank you! :smile:

siddharth
Oct6-05, 02:12 AM
tatoo5ma, Instead of expanding sin(a+b), what else can you do? If you write it as a trignometric function of (a+b)/2 can you see what happens?

Integral
Oct6-05, 03:37 AM
sure

Sin (a+b) = Sin (2(a+b)/2) = 2 cos((a+b)/2)Sin((a+b)/2)

mohlam12
Oct6-05, 08:22 AM
yeah, then u can factor with Sin((a+b)/2) and then make cos((a-b)/2)+cos((a+b)/2) equal to 2cos(a/2)cos(b/2) and u have everythin factorized :smile: