Determining Tension in a Frictionless System with Given Mass and Tension

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SUMMARY

The discussion focuses on solving a physics problem involving tension in a frictionless system with a mass of 4.0 kg and a tension of 12 N in string 1. The objective is to determine the force F that accelerates interconnected blocks. Using Newton's 2nd law, participants confirm that the net force is 45 N and the acceleration is 5 m/s², leading to the conclusion that the correct answer for F is 25 N.

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  • Understanding of Newton's 2nd Law of Motion
  • Basic knowledge of tension in interconnected systems
  • Familiarity with frictionless surfaces in physics
  • Ability to calculate net force and acceleration
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  • Study the application of Newton's 2nd Law in multi-body systems
  • Learn about tension forces in connected objects
  • Explore frictionless motion and its implications in physics problems
  • Practice solving problems involving net force and acceleration calculations
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Students studying physics, particularly those preparing for AP Physics exams or anyone interested in understanding dynamics in frictionless systems.

physixnot4me
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Hi! If anyone could pass on any hints as to how to go about figuring out this type of problem...thanks! I just need guidance as to how to determine F... attached is a diagram.

The horizontal surface on which the object slides is frictionless. If M=4.0kg, the tension in string 1 is 12N. Determine F in N.

a) 10 b) 20 c) 25 d) 40 e) none of the above
 

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All the blocks are interconnecrted so have the same acceleration. The force F accelerates all three blocks.
The tension, T1, accelerates the last two blocks with the same acceleration.

Use Newton's 2nd law.
 
While we're on the topic of tension (which I never really learned last year in ap physics b), can anyone show me where to start on this problem? I'm really regretting taking ap physics c, but I got a 5 on the exam for b so I can't be that bad, right?
2hd5mdz.jpg


I've determined the net force is 45 N and that the acceleration must be 5 m/s2, but that's about it :/
 

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