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newton1
Apr8-03, 11:17 AM
how to solve the x from x^4+x^3.....=...??
i mean from the equation for x power of 4
like the x^2-2x+1=0
the solve are x=1,x=1

ottjes
Apr8-03, 12:45 PM
substitution

eg. x^4 + x^2 = 0
now y=x^2
--> y^2 + y = 0

you can solve this for y (= x^2)

lethe
Apr8-03, 02:58 PM
the full solution of the quartic equation is fairly long. so rather than retyping a lot of calculations, i will link you to a solution here (http://mathworld.wolfram.com/QuarticEquation.html)

damgo
Apr8-03, 05:51 PM
Cutely, it's provable that you can't find a general solution (using addition/subtraction, multiplation/division, and roots) for polynomials in any order higher than quartic. The proof uses the same technique (Galois theory, loosely) as the geometric nom-constructibility proofs for things like trisecting an angle.

Loren Booda
Apr9-03, 12:27 AM
How effective is the p/q method for finding roots of quartics or higher order polynomials? Remind me how it works for a simple example.

lethe
Apr9-03, 01:14 AM
Originally posted by Loren Booda
How effective is the p/q method for finding roots of quartics or higher order polynomials? Remind me how it works for a simple example.

what is the p/q method?

the quartic solution is 100%. it is guaranteed to give you four exact analytic roots to your quartic.