How Do Currents in Adjacent Wires Affect Their Mutual Force?

  • Thread starter Thread starter jena
  • Start date Start date
  • Tags Tags
    Force Wires
Click For Summary
SUMMARY

The discussion centers on calculating the net force on a rectangular loop of wire due to a straight wire carrying a current of 2.5A. The user initially calculated the force using the formula F=((μ₀)(I)²(length))/(2π(distance)), resulting in F=2.5 x 10^-6 N, which did not match the textbook answer of F=2.6 x 10^-6 N. The error was identified as a miscalculation of the distance from the straight wire to the segment of the loop being analyzed, as well as not considering the contributions from each segment of the loop.

PREREQUISITES
  • Understanding of Ampère's Law and magnetic forces between current-carrying wires
  • Familiarity with the Biot-Savart Law for calculating magnetic fields
  • Knowledge of basic geometry related to rectangular loops and distances
  • Proficiency in using the permeability constant (μ₀) in calculations
NEXT STEPS
  • Review the Biot-Savart Law for calculating magnetic fields around current-carrying conductors
  • Learn how to calculate the net force on multiple segments of a wire loop
  • Study the effects of distance on magnetic force calculations in electromagnetism
  • Practice problems involving mutual forces between parallel wires and loops
USEFUL FOR

Physics students, electrical engineers, and educators seeking to understand the interactions between current-carrying wires and the forces they exert on each other.

jena
Messages
74
Reaction score
0
Hi,

My Question:

A rectangular loop of wire lies in the same plane as a straight wire, as show in Fig. 20-57. There is a current of 2.5A in both wires. Determine the magnitude and direction of the net force on the loop.

http://www.webassign.net/pse/p31-09.gif"

where the width is 10.cm and width of the box is 5.0 cm and distance from the rectangular loop and the straight wire is 3.0 cm.

My Work

F=((mu constant)(I)^2(length))/(2pi(distance))
F=((4pi x 10^-7 Tm/A)(2.5A)^2(.10m))/(2pi(.05m))
F=2.5 x 10^-6 N

but the answer in the back of the book gives F=2.6 x 10^6

What did I do wrong:confused:

Thank You:smile:
 
Last edited by a moderator:
Physics news on Phys.org
You need to calculate the force on each segment of the loop due to the long straight wire, and add them up. It looks to me like you only attempted to calculate the force on a single segment.

It also looks like you've plugged in the wrong distance (that's supposed to be the distance from the straight wire to the segment you are analyzing).

And this bit here is confusing:

where the width is 10.cm and width of the box is 5.0 cm and distance from the rectangular loop and the straight wire is 3.0 cm.

Which one is the "width"?
 
Sorry,

http://www.webassign.net/pse/p31-09.gif"

width=5 cm
Length= 10 cm
height= 3 cm

I thought the width would be used for the distance, but I guess that's wrong. I tried plugging in number but with no results close to the textbook answer of 2.6 x 10^-6 N

I still don't know what I did wrong though:confused:

Please help and Thank You
 
Last edited by a moderator:

Similar threads

Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
12K
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
18
Views
4K