Calculate Horizontal Force & Power Output for 50kg Sprinter

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SUMMARY

The discussion centers on calculating the horizontal force and power output of a 50kg sprinter who runs 50m in 7.0 seconds with constant acceleration. The correct approach involves using kinematics equations rather than average velocity to determine acceleration. Specifically, the equation d = v_it + (1/2)at^2 should be applied to find acceleration, which can then be used in Newton's second law (F = ma) to calculate the force. The initial calculations presented were incorrect due to the misuse of average velocity principles.

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  • Understanding of Newton's second law (F = ma)
  • Familiarity with kinematics equations
  • Basic knowledge of acceleration and velocity concepts
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maki
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A 50kg sprinter, starting from rest, runs 50m in 7.0s at constant acceleration.
a) What is the magnitude of the horizontal force acting on the sprinter?
b) What is the sprinter's power output at 2.0s, 4.0s, and 6.0s?
I think maybe the 'magnitude' part is confusing me.
F = ma
V(avg) = (50-0)/(7-0) = 50/7
A = (50/7)/7 = 50/49
F= 50kg * 50/49
F is exactly half of what the answer in my book says, what do I need to do and why?
Thank You,
in advance =o
 
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Because the question explicitly states that there is a constant acceleration you cannot use the average velocity principle. You should instead refer to your kinematics equations:

[tex]d = v_it + \frac{1}{2}at^2[/tex]

and solve for the acceleration. Once you get acceleration, as you have shown you understand, you may apply it to Newton's second law.
 
works so much better that way, ty ;p
 

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