What is the Solution to the Roller Coaster Apparent Weight Problem?

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Homework Help Overview

The discussion revolves around a physics problem involving a roller coaster with a circular vertical loop, specifically focusing on the apparent weight experienced by a rider at the top and bottom of the loop. The original poster expresses frustration in solving the problem and seeks assistance in understanding the concepts involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants inquire about the original poster's attempts and suggest considering the centripetal force required at different points in the loop. There is a focus on the relationship between weight, gravitational force, and acceleration in the context of the problem.

Discussion Status

The discussion is ongoing, with some participants prompting the original poster to clarify their previous attempts and where they encountered difficulties. A hint regarding the centripetal force has been provided, indicating a potential direction for further exploration.

Contextual Notes

The original poster notes that this problem is part of an MCAT review, which may imply specific constraints or expectations regarding the problem-solving approach.

joseph harris
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Show that a roller coaster with a circular vertical loop. The difference in your apparent weight at the top of the circular loop and the bottom of the circular loop is 6 g's-that is, six times your weight. Ignore friction. Show also that as long as your speed is above the minimum needed, this answer doesn't depend on the size of the loop or how fast your go through it. I tried solving this but I'm very frustrated can anyone help?:smile:
 
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We do need to see what you've already tried, so we know you aren't just trying to get an easy answer out of us.

A quick hint, though - have you considered the centripetal force necessary, and where that force is going to come from? It'll be different at the top of the loop and at the bottom.
 
Pls explain what you tried and where you got stuck.
 
Diane,

I have used the relationship of: w-MG=MA Solving for w We have W+Mg+MA

W+MG+m(.5g)=3/2mg. I still have not been able to solve. This is not a homework problem but a MCAT review problem. Thanks
 

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