Partial Integration for [tex]\frac{xarctan(x)}{(1+x^2)^2}[/itex]

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Homework Help Overview

The discussion revolves around the integration of the function \frac{xarctan(x)}{(1+x^2)^2}. Participants are exploring methods of integration, particularly focusing on the concept of partial integration or integration by parts.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss different approaches to integration, including various choices for u and dv in the integration by parts method. There is confusion regarding the terminology of "partial integration" versus "integration by parts." Some participants question the effectiveness of certain choices for u and dv, suggesting that they complicate the integrand.

Discussion Status

The discussion is ongoing, with participants providing insights into their thought processes and the challenges they face in finding suitable forms for integration. There is no explicit consensus, but some guidance has been offered regarding potential choices for u and dv that may simplify the integrand.

Contextual Notes

Participants are navigating the complexities of integration techniques and are encouraged to clarify their initial approaches before proceeding. There is an emphasis on examining the integrand closely before attempting integration.

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How do I integrate:
[tex]\frac{xarctan(x)}{(1+x^2)^2}[/itex][/tex]
 
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You have to show us how you started first.
 
Tom Mattson said:
You have to show us how you started first.

How I started first? I tried with partial integration in many different ways.. :bugeye:
 
What do you mean by "partial integration"? I've only heard that term used in reference to integrals of functions of several variables. Did you mean to say, "integration by parts"? If so, then please show us what you did.
 
Before you integrate something, it's always good to spend some time to look at it closely.
Now if you choose u = x, and dv = (arctan(x)dx) / (1 + x2)2, then it's very hard to find v.
If you choose u = x / (1 + x2)2, and dv = arctan(x)dx, then you'll get a mess when you try to find du, and obviously, you are complicating the integrand.
And if you choose u = 1 / (1 + x2)2, and dv = x arctan(x) dx, then it's hard to find v.
...
And if you choose u = arctan(x), and dv = (x dx) / (1 + x2)2, you can make the integrand look simplier. Now just try it.
You then come up with something like:
[tex]\int \frac{dx}{(1 + x ^ 2) ^ 2}[/tex], you can again try to integrate it by parts.
Viet Dao,
 
Last edited:

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