Question Concerning F=ma and FBDs.

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Homework Help Overview

The discussion revolves around the application of Newton's second law, F=ma, in the context of free body diagrams (FBDs). The original poster seeks clarification on the order of forces when calculating the net force acting on an object, specifically in scenarios involving tension and weight.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand how to determine the order of forces in the equation \sum F = ma when acceleration is present. Some participants discuss the implications of choosing different positive and negative directions for force components.

Discussion Status

Participants are exploring different interpretations of how to apply the force equations based on direction choices. There is an acknowledgment that the order of forces can affect the sign of acceleration, but no consensus has been reached on a definitive approach.

Contextual Notes

There is a mention of specific scenarios, such as the Atwood machine, where the arrangement of forces may need to be consistent for clarity. The discussion also touches on the importance of understanding the implications of direction choices in force calculations.

lawtonfogle
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Ok, I know that, using a FBD, one is susposed to use [tex]\sum F = m a[/tex]
My question is what order do you put the forces that [tex]\sum F[/tex] equal
An example might help me explain my question.
Lets take a block of wood that is supported by a string. The only forces acting on it are [tex]mg[/tex] and [tex]T[/tex]
So...
[tex]\sum F = ma[/tex]
[tex]T - mg = ma[/tex]
or
[tex]mg - T = ma[/tex].
I know if [tex]a = 0[/tex] it does not matter, but how does one decide what order to put th forces in when there is acleration?
 
Last edited:
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The [tex]\sigma[/tex] should be a capital sigma.I fixed it.
 
Last edited:
It depends on how you choose the positive and negative directions.
T - mg = ma1, you've chosen the positive direction upwards.
mg - T = ma2, you've chosen the positive direction downwards.

T - mg = ma1 = -(mg - T) = -ma2

In the case that mg is greater than T, the acceleration's negative when you've chosed the positive direction upwards, and positive when you've chosen the positive direction downwards. The magnitude does not change.
 
So on an Atwood machine, I should chose it so that both masses are the same way written (both T - mg, or vice versa), or so that the greater force is first.
 

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