Neeed help with a laplace transform

Click For Summary

Homework Help Overview

The discussion revolves around the Laplace transform, specifically focusing on the function involving the Heaviside step function, \(\theta(t)\), and its interaction with \(\cos(t)\). Participants are exploring the implications of piecewise functions in the context of Laplace transforms.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are attempting to understand how to apply the Laplace transform to a function that includes \(\theta(t)\) and \(\cos(t)\). There are questions about the significance of \(\theta(t)\) and whether it can be ignored in certain contexts. Some participants are also discussing the piecewise nature of the function and its implications for the transform.

Discussion Status

The discussion is ongoing, with participants providing insights into the role of \(\theta(t)\) and its effect on the Laplace transform. There is a recognition of the need to consider the function's behavior for \(t < 0\), and some guidance has been offered regarding the piecewise definition of the function.

Contextual Notes

There are references to specific textbook definitions and guidelines from the forum regarding the necessity of showing attempts before receiving help. Participants are also discussing the use of special symbols in their posts.

Lorens
Messages
29
Reaction score
0
What is the laplace transform of

http://img150.imageshack.us/img150/8145/laplacetransform6wk.jpg
 
Last edited by a moderator:
Physics news on Phys.org
According to the section entitled "Homework Help" in the Physics Forums Global Guidelines which you agreed to:

NOTE: You MUST show that you have attempted to answer your question in order to receive help.

So what are you got?
 
Tom Mattson said:
According to the section entitled "Homework Help" in the Physics Forums Global Guidelines which you agreed to:
So what are you got?

It isn't so much to test, just to watch a tabel of formula, i know the transform for cos(x), but i can't find any rule which would let me multiplicat it with O(x).

I mean for problems like this you just think, and try to figure out how to do it.
I would say my problem is O(x).

Anyway i got to go to bed now 00:08.. lol...
 
Do you know what [itex]\theta(t)[/itex] is?
 
Tom Mattson said:
Do you know what [itex]\theta(t)[/itex] is?


for [itex]\theta(t)[/itex] t<0 gives t=0 and t>0 gives t=1 and the transform is 1/s, but that knowledge don't help me much :( ...
 
You are right about [itex]\theta(t)[/itex], but that knowledge should help you a great deal.

You have a function that is defined piecewise:

[tex]\theta(t) = \left\{ \begin{array}{cc}0 & t<0\\1 & t \geq 0\end{array}[/tex]

Now, if you multiply [itex]\theta(t)[/itex] by [itex]\cos(t)[/itex], then you just have to multiply both pieces by [itex]\cos(t)[/itex].

So...

[tex]\cos(t)\theta(t) = \left\{ \begin{array}{cc}0 & t<0\\\cos(t) & t \geq 0\end{array}[/tex]

Can you take it from there?
 
Last edited:
You missed that [itex]\theta(o)[/itex]=1/2 my textbook say so, but it don't matter.

Can I ignore [itex]\theta(t)[/itex] seen the laplace transform isn't defined for the second quadrant for the x-axis.

Also i must ask how do you get access to all the special signs?

Thx for your time Lorenz
 
Lorens said:
Can I ignore [itex]\theta(t)[/itex] seen the laplace transform isn't defined for the second quadrant for the x-axis.
It's not a matter of being undefined, but you got the right idea. It's more precise to state that the laplace transform of f doesn't care what values f takes on for x<0.

Also i must ask how do you get access to all the special signs?
Thx for your time Lorenz
What special signs?
 
Like [itex]\theta(t)[/itex] i just copyed him there :smile:
 
  • #10

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K