Calculating Force of Falling Weight in Closed System

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The discussion focuses on calculating the force of a falling weight in a closed system involving a cart and a pulley. The correct approach to determine the force is to use the formula F = ma, where 'a' is the acceleration of the cart, not simply the gravitational force (F = mg). The net forces acting on the falling weight include the force of gravity (Fg1) and the tension in the rope (FT). The tension cancels out when analyzing the entire system, leading to the equation Fnet = (m1 + m2)a = Fg1 + Ff2.

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jesuslovesu
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I'm just wondering if I'm doing this correctly..

If I have something like this: http://img326.imageshack.us/my.php?image=pull6cx.png

It's a closed system where the weights on the cart will get placed on the bottom holder for each trial... To find the 'force of the falling weight' I would take the mass*acceleration, where acceleration is determined by how fast the cart goes in a certain distance right? I wouldn't just take the mass*gravity when it's connected to a pulley like that would I?
 
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The only forces acting on the falling weight are Fg1 (force of gravity) and FT (force of tension in the rope). For the falling weight alone, Fnet1 = ma = Fg1+FT.

Since FT is applied in both directions in the rope, it "cancels out" when you involve the entire system. For the entire system, Fnet = (m1+m2)a = Fg1+Ff2.

Hope that helps.
 

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