Calculating Spring Constant with a Mass on a Compressed Spring - Simple Solution

Click For Summary

Homework Help Overview

The problem involves calculating the spring constant of a massless spring that is compressed and then releases a mass, which travels vertically. The context includes the use of energy conservation principles and the effects of gravitational acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply conservation of energy to find the spring constant but expresses uncertainty about the forms of energy involved. Some participants clarify the distinction between the spring's compressed length and the distance compressed.

Discussion Status

The discussion has led to a clarification regarding the calculation of the spring's compression distance. Participants are exploring the implications of this clarification on the original approach without reaching a consensus on the final solution.

Contextual Notes

The original poster assumes that the time for the spring to reach full extension is negligible, which may influence the interpretation of the problem. There is also a focus on ensuring the correct application of energy conservation principles.

Punchlinegirl
Messages
221
Reaction score
0
A massless spring of length .310 m is compressed to 71.0 % of it's relaxed length, and a mass M=.150 kg is placed on top and released from rest. The mass then travels vertically and it takes 1.10 s for the mass to reach the top of its trajectory. Calculate the spring constant, in N/m. Use g= 9.81 m/s^2. Assume that the time required for the spring to reach its full extension is negligible.

I really have no idea how to do this problem. I tried using conservation of energy and solving for k, I'm not sure if I even have all of the forms of energy
(1/2)kx^2= (1/2)mv^2
(1/2)k(.2201)^2= (1/2)(.150)(10.78^2)
to get 360.0 N/m , which wasn't right


Any help would be appreciated. Thanks
 
Physics news on Phys.org
When you multiply .310 m by 71%, what you're getting is the length of the spring when compressed. The x in the equation you're using is the distance it's compressed, not its new length.

Does that do it?
 
Yes.. that's what I was doing wrong. Thanks
 
We live to serve. ;)
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
17
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
Replies
29
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K