What is the force required to lift a car using hydraulic pistons?

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SUMMARY

The force required to lift a car weighing 12,000 N using hydraulic pistons can be calculated using Pascal's principle, which states that pressure is transmitted equally in a fluid. Given a small piston diameter of 0.32 m and a large piston diameter of 1.4 m, the relationship between the forces and areas of the pistons can be established. The pressure exerted by the small piston must equal the pressure exerted by the large piston, leading to the formula F1/A1 = F2/A2, where F1 is the force on the small piston and A1 is its area, while F2 is the force on the large piston and A2 is its area.

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  • Understanding of Pascal's principle in fluid mechanics
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Engineers, mechanics, and students studying fluid mechanics or hydraulic systems, particularly those interested in automotive applications and hydraulic lifting mechanisms.

WhatTheBleepDoIKnow
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This is the last one I need some help with...

What force must be applied to a small cylinder piston with a diameter of .32m to lift a car weighing 12,000 N that is supported by the piston in a large cylinder that has a diameter of 1.4m? Assume that there is an enclosed chamber in common between the two pistons and that the chamber is filled with hydraulic oil.

Thanks
 
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Hint: Pascal's principle implies that the pressure must be the same for both pistons.
 

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