Finding Derivative of V= ay/(b2 + y2) - Help Needed

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Homework Help Overview

The discussion revolves around finding the derivative of the function V = ay/(b² + y²) with respect to y. The subject area is calculus, specifically focusing on differentiation techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express confusion about the concept of derivatives and seek clarification on the problem. Some provide examples of derivatives and attempt to apply the quotient rule to the given function.

Discussion Status

There is an ongoing exploration of the derivative with some participants sharing their attempts and methods. Guidance has been offered regarding the use of the quotient rule, but no consensus or complete solution has been reached.

Contextual Notes

Some participants indicate a lack of recent experience with math, which may affect their understanding of the problem. There is an emphasis on not providing direct answers but rather assisting with understanding the process.

Kali8972
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Partial integral?

Can someone help me figure out what this means? It's been forever since I've had any math classes.

V= ay/(b2 + y2)

Find the derivative in terms of a,b, and y

Thanks so much!
 
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Kali8972 said:
Can someone help me figure out what this means? It's been forever since I've had any math classes.
V= ay/(b2 + y2)
Find the derivative in terms of a,b, and y
Thanks so much!
Do you know what a derivative is? Nobody here is going to just do the problem for you, but if you show what you're having trouble with we'll try to help :smile:
 
yes... For example if you had 2x^3 the derivative would be 6x^2... When i do the derivative for the above equation I get:
a(b^2-y^2)/(b^2+y^2)^2
 
Use the "quotient rule": the derivative of [itex]\frac{f(y)}{g(y)}[/itex] is
[tex]\frac{\frac{df}{dy}g(y)- f(y)\frac{dg}{dy}}{g^2}[/tex]
 

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