Calculating Work Done by a Force on a Block

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SUMMARY

The discussion focuses on calculating the rate of work done by a force on a 190kg block being pulled at a constant speed of 4.8m/s with an applied force of 130N at an angle of 37 degrees above the horizontal. To determine the power, the correct approach involves using the formula P = F * v * cos(θ), where F is the force, v is the velocity, and θ is the angle. Participants emphasize the importance of understanding the definition of work and the implications of the angle on the calculation.

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  • Understanding of Newton's laws of motion
  • Familiarity with the concept of work and power in physics
  • Knowledge of trigonometric functions, specifically cosine
  • Ability to perform basic calculations involving force and velocity
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Okay, the question is:

A 190kg block is pulled at the constant speed of 4.8m/s across a horizontal floor by an applied force of 130N directed 37deg above the horizontal. What is the rate at which the force does work on the block? (in W)

to find this, would i multiply 130by cos(37), then by 4.8 to get work/sec?
 
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A couple of points;

- Consider what would happen if the force was applied parallel to the surface (so the angle is zero). Do you still think you should take the cosine?
- Review the definition of work. What quantities do you then need to calculate to find the amount of work done per second?

Also, this thread should be moved to the Homework Help section.

Claude.
 

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