What Is the Normal Force Acting on a Box Pulled by a Mule?

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The normal force acting on a box being pulled by a mule is determined by analyzing the forces at play. Given that the box weighs 300 Newtons and the tension in the rope is 100 Newtons at a 30-degree angle, the normal force can be calculated using the equation: Normal Force = Weight - Vertical Component of Tension. The vertical component of the tension is 100 * sin(30°), which equals 50 Newtons. Therefore, the normal force is 300 - 50 = 250 Newtons.

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A mule uses a rope to pull a box that weighs 3.0 times ten to the second Newtons across a level surface with constant velocity. The rope makes an angle of thirty degrees above the horizontal, and the tension in the rope is one times ten squared Newtons. What is the normal force of the floor on the box?

I think I know how to do this problem but the main problem is that I don's know what a tension force is.
 
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The tension force is the force transferred through the rope
 

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