How Much Lead Can a Tin Cup Carry Without Sinking?

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Homework Help Overview

The problem involves determining how much lead a tin cup can carry without sinking in water, given the cup's volume and mass, as well as the density of lead. The subject area includes principles of buoyancy and fluid mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate the forces acting on the tin cup and questions how to calculate the buoyant force. Other participants discuss Archimedes' Principle and the relationship between the volume of water displaced and the buoyant force.

Discussion Status

The discussion is actively exploring the concepts of buoyancy and the calculations needed to find the buoyant force. Some guidance has been offered regarding the relationship between the volume of the cup and the weight of the displaced water, but no consensus has been reached on the specific calculations.

Contextual Notes

Participants are working with the constraints of the problem, including the specific volume and mass of the tin cup, as well as the density of lead. There may be assumptions about the conditions under which the cup is floating that are not explicitly stated.

r3dxP
A tin cup has a total volume of .012m^3 and mass of .13kg. How many grams of lead shot of density 11.4g/cm^3 could it carry without sinking in water?

the question i have here is what is equal to what and how to solve this?
so far.. i have.. Ftin = Vpg = .012m^3 * 7310kg/m^3 * 9.8m/s^2 = 860N
the tin alone pushes down 860N onto the water.
how can i find the force pushed by the water in the sink? cause once i find this force, i can set the equation.. Ftin + Flead = Fwater
once i get the Flead, i can solve for mass by Flead / g..
 
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And Archimedes' Principle rears its attractive head for the second time in twenty-four hours.

The buoyant force will equal the weight of the water displaced by the cup.
 
how can i solve for the buoyant force?
 
You know the total volume of the cup - you therefore know the maximum amount of water it can displace, yes? Just find the weight of that much water and Bob's your uncle.

Clear?
 

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