Light that has enough energy to cause this bond to break?

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SUMMARY

The discussion centers on calculating the longest wavelength of light capable of breaking Cl2 bonds, which requires 242.7 kJ/mol of energy. To find the energy per molecule, divide this value by Avogadro's number (6.02 x 10^23). The wavelength can then be determined using the formula λ = (E × c) / h, where E is the energy per photon, c is the speed of light (approximately 3 x 10^8 m/s), and h is Planck's constant (6.63 x 10^-34 J·s).

PREREQUISITES
  • Understanding of bond dissociation energy
  • Familiarity with Avogadro's number
  • Knowledge of the equation λ = (E × c) / h
  • Basic grasp of quantum mechanics principles
NEXT STEPS
  • Calculate the energy per molecule for Cl2 using 242.7 kJ/mol
  • Research the implications of bond energy in chemical reactions
  • Explore the relationship between wavelength and energy in photons
  • Learn about the applications of Planck's constant in quantum physics
USEFUL FOR

Chemistry students, educators, and professionals involved in molecular chemistry and photochemistry who seek to understand the energy requirements for bond dissociation.

jewilki1
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I really need help with this problem. I need to know how to work it and the answer. I am trying to review all these problems and they do not have answers.
2. It requires 242.7 kJ/mol to fragment Cl2 molecules into Cl atoms. What is the longest wavelength (in nanometers) of light that has enough energy to cause this bond to break?

Could you please explain this to me? I have the answer: 242.7 kJ/mol. Is this right?

Thanks.
 
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To find the energy required to cause one bond to break you would have to divide the energy that is given for one mol of [tex]Cl_{2}[/tex] molecules to fragment into [tex]Cl[/tex] atoms by the number of [tex]Cl_{2}[/tex] molecules in one mol. There are [tex]6.02 \times 10^{23}[/tex] [tex]Cl_{2}[/tex] molecules in one mol.

Then when you've found this amount of energy you can find the photon wavelength required to produce it by using the equation:

[tex]\lambda = \frac {E \times c}{h}[/tex]

Where [tex]\lambda[/tex] is the longest wavelength required to fragment the molecules as the calculation assumes no energy is lost, E is the energy of the photon, c is the speed of light (about [tex]3 \times 10^8[/tex]) and h is Planck's constant ([tex]6.63 \times 10^{-34}[/tex]).
 

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