Does -e^(-infinity) Equal 0 in Mathematics?

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Homework Help Overview

The discussion revolves around the mathematical expression involving the limit of the exponential function as the exponent approaches negative infinity, specifically questioning whether -e^(-infinity) equals 0.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the limit of e^x as x approaches negative infinity and its implications for the expression -e^(-infinity). There is a specific inquiry about the notation and whether it aligns with the limit notation.

Discussion Status

Some participants have provided insights regarding the limit of e^(-x) as x approaches infinity, suggesting that it approaches 0. The conversation indicates a progression towards understanding the relationship between the limit and the original expression, though no consensus has been reached.

Contextual Notes

Participants are discussing the mathematical properties of limits and exponential functions, with a focus on notation and interpretation of expressions involving infinity.

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does -e^(-infinity) equals 0?
 
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The limit of e^x as x-->-infinity is 0.
 
Are you referring to [itex]\lim_{x\rightarrow\infty} -e^{-x}[/itex] ?
 
yes...
 
As kamataat said, [itex]\lim_{x\rightarrow\infty} e^{-x}= 0[/itex] and so
[itex]\lim_{x\rightarrow\infty} -e^{-x}= -0= 0[/itex].
 
i see. thanks.
 

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