Work phythagorean theorem Question

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SUMMARY

The discussion centers on calculating work done in physics problems involving the Pythagorean theorem and forces. A rectangular marble slab measuring 3.4m by 2.0m and weighing 180kg requires 3000 Joules of work to stand on end, calculated using the formula work = force x distance. The user also discusses two additional questions involving a 200kg cart pushed up an incline, where the work done is calculated as 2940 Joules without friction and 3990 Joules with a frictional force of 150N. The calculations involve understanding the relationship between force, distance, and friction.

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SS2006
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this is drivnig me nuts I've doen eveyrthin gon the worksheet but this is a weird one


A unifrom rectangular marble slab is 3.4m long and 2.0m wide. It has a mass of 180KG. If it is originally lying on the flag ground, how much work is needed to stand it on end.

I know work = force X distance
and to get force i multiply 180X9.8 like I've doen in all the other questions
but what's the distance here it rises, it ried phythagorean theorem to get the distance and all these weird aways
but the asnwer should be
3000 J
dont nkow what to do!
thanks
 
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and another
Q1 was)
A 200 kg cart is pushed slowly up an incline. How much work does the pushing force do in moivng the cart up to a platorm 1.5m above the starting point if frciton is negligible

that was fairly easy, (200X9.8) = 1960 X 1.5 = 2940 J

Q2 is )
Repeat Q1 if the distance along hte incilne to the platofrom is 7m and a fricotin force of 150N opposes the motion.
I didnt know how to handle this, but i see doing 7X150 = 1050
and adding that to the first asnwer 2940J gives me the right answer
3990
can anyone expalin why this worked?
i thoguht id have to do 1960X7 instead and what would i do with force
 
please ppl!
 

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