How Is the Change in Linear Momentum Calculated in a Collision?

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SUMMARY

The change in linear momentum during a collision is calculated by considering the initial and final velocities of the mass involved. In this case, a 0.118 kg mass moving at 8.49 m/s rebounds at 1.07 m/s. The correct formula for calculating the change in momentum is ΔP = mv1 + mv2, where v1 is the initial velocity and v2 is the final velocity, treated as a positive value due to direction. The magnitude of the change in linear momentum is 1.128 kg m/s.

PREREQUISITES
  • Understanding of linear momentum and its formula (P = mv)
  • Knowledge of vector quantities and their directional properties
  • Familiarity with basic physics concepts related to collisions
  • Ability to perform calculations involving mass and velocity
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  • Study the principles of conservation of momentum in collisions
  • Learn about elastic and inelastic collisions and their effects on momentum
  • Explore vector addition and subtraction in physics
  • Investigate real-world applications of momentum calculations in sports or vehicle collisions
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A 0.118 kg mass is moving horizontally with a speed of 8.49 m/s when it strikes a vertical wall. The mass rebounds with a speed of 1.07 m/s. What is the magnitude of the change in linear momentum of the mass?

isn't the change just the difference in momentum? I did .118(8.49 - 1.07) to get .87556 kg m/s. this is wrong so i think the answer is .118(8.49+1.07) because it would be minus a negative velocity. so i got 1.128 kg m/s. but i don't know if this number should be negative or not.
 
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The change is, as you say, just the differnce in momentum.

But momentum is mv. And v (the velocity) is a vector and has a direction.
So deltaP = mv1 - mv2, but v1 and v2 are in opposite directions, so you have to (numerically) add them.

Since you are asked for a differnce, then take the absolute value, i.e. positive.
 

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