Optimization Problem Solution - Checking and Verification

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    Optimization
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Homework Help Overview

The discussion revolves around an optimization problem, with participants reviewing a solution presented by the original poster. The problem appears to involve calculus concepts, particularly related to derivatives and possibly integrals.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster seeks verification of their solution, while one participant notes a broken link and offers feedback on the clarity of the work. They suggest checking the first derivative to eliminate a potential solution and express a preference for clearer arithmetic presentation.

Discussion Status

The discussion includes constructive feedback on the original poster's solution, with one participant affirming the correctness of the work while also providing suggestions for improvement. There is no explicit consensus, but the feedback appears to guide the original poster towards refining their solution.

Contextual Notes

One participant mentions a broken link to part of the solution, which may limit the ability to fully assess the original poster's work. Additionally, there are indications of specific preferences regarding presentation style that may not align with academic expectations.

opticaltempest
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Is anyone willing to check my solution to this problem? The problem is described on part 1 of the solution.

http://img458.imageshack.us/img458/5418/solution016dj.jpg"

http://img458.imageshack.us/img458/7669/solution025zk.jpg"

http://img458.imageshack.us/img458/6652/solution030fr.jpg"

http://img458.imageshack.us/img458/3950/solution048zi.jpg"

http://img458.imageshack.us/img458/7357/solution059yw.jpg"

Thanks
 
Last edited by a moderator:
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I'm getting a broken link on your page two, but it doesn't matter. Your work is fine - well laid out and correct.

Two things: 1) You can also eliminate r=0 as a solution by checking the first derivative in its vicinity. It leads to a maximum, as you might guess.

2) I'm not extraordinarily fond of the way you express h. If I were your professor, I'd ask you to clean up the arithmetic a bit - but that's your call and his.

Good job.
 
Thanks for checking it over Diane_
 
[tex]1/2\,{v}^{2}={\frac {{\it GM}}{y}}[/tex]
 
[tex]\[\int \!v{dv}=-{\it GM}\,\int \!{y}^{-2}{dy}\]}[/tex]

testing out latex... ignore last two replies by me
 
Last edited:

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