Comparing Electric Field Strengths at Two Points: Positive and Neutral Charges

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SUMMARY

This discussion focuses on comparing electric field strengths at two points influenced by positive charges. The analysis reveals that at point 1, the electric field is calculated as (k/r²)*2q due to the repulsive effect of nearby charges, while at point 2, the field strength is (k/r²)*3.111q, benefiting from the additive effect of the surrounding charges. Consequently, point 2 exhibits a stronger electric field than point 1. The conclusion is that the configuration and interaction of charges significantly affect the resultant electric field strength at given points.

PREREQUISITES
  • Understanding of Coulomb's Law and electric field calculations
  • Familiarity with the concept of superposition of electric fields
  • Knowledge of vector addition in physics
  • Basic grasp of charge interactions (repulsion and attraction)
NEXT STEPS
  • Study Coulomb's Law and its applications in electric field calculations
  • Learn about the superposition principle in electric fields
  • Explore vector addition techniques for combining electric field vectors
  • Investigate the effects of charge configuration on electric field strength
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric field interactions and calculations.

dekoi
I am posed with a question, there are two charges, both positive, and two neutral points.

I am asked to compare the electric field strengths at the two points.

Here is a pictorial representation:

[tex]\bigoplus[/tex]------->[tex]\bullet 1[/tex]<-------[tex]\bigoplus\bigoplus\bigoplus[/tex]------->[tex]\bullet 2[/tex]

The three +s in a row represent one big positive charge.

So I drew my electric field lines (represented by the arrows), and now I have to analyze whether the field strengths at the two points are different, or equal.

At first I thought that 1 > 2, since 1 has respectively four positive charges at it, while 2 only has three positive charges.
However, then I thought:
In the case of 1, the two electric fields will repel each other, and then there will no ( ? ) field lines around 1, in which case 2 > 1.

But I don't have much proof to back up my answer, and my textbook doesn't explain this in great detail (neither did my teacher). Any suggestions on how to compare electric field strengths?

Thanks.
 
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If the two points are of equal distance to the big charge then the field at point 2 will be bigger, here's why:
the total field at point 1 is (k/r^2)*3q - (k/r^2)*q = (k/r^2)*2q the (-) is to show that they are in oppisite directions
the total field at point 2 is (k/r^2)*3q + (k/9r^2)*q = (k/r^2)*3.111q
anyway in point 1 the small charge takes away from the big one, at point 2 it adds to it.
 

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