Waves (Sinos., Interference, etc.)

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SUMMARY

The discussion focuses on wave mechanics, specifically addressing the equations of motion for a string and the concept of phase difference in wave interference. The equation for the motion of a point on a string at x = 1.5m is derived as y = 0.1sin(-(pi)t) by substituting x into the original equation. Additionally, the phase difference of 2.0 radians with an angular frequency of 4 rad/s translates to a time period of 0.5 seconds, illustrating the relationship between phase and time. The discussion also explores locating points of destructive interference between two speakers driven in phase at 800Hz.

PREREQUISITES
  • Understanding of wave equations and sinusoidal functions
  • Knowledge of phase difference and angular frequency in wave mechanics
  • Familiarity with concepts of interference and nodes in wave patterns
  • Ability to calculate wavelength using the formula v/f
NEXT STEPS
  • Study the derivation of wave equations in one-dimensional strings
  • Learn about the relationship between phase difference and time in wave mechanics
  • Explore the principles of constructive and destructive interference
  • Investigate the calculation of nodes and antinodes in wave patterns
USEFUL FOR

Physics students, educators, and anyone interested in understanding wave mechanics, particularly in the context of sound and string vibrations.

dekoi
1.) Suppose the equation for the left end of a string is y = 0.1sin((pi)x - (pi)t).
What would be the equation for the motion of the point on the string at x = 1.5m to the right of the left end. Apparently, x is set to zero to yield the equation y = 0.1sin(-(pi)t). But I don't understand why. Any explanation is helpful.

2.) If i have determined the phase difference of a wave to be 2.0 rad, and I also have angular frequency (4 rad/s), how would i determine the phase in terms of time? Apparently its phase / angular frequency (so, 0.5sec), but I don't understand this conceptually.

3.) Two speakers are driven in phase by a common oscillator at 800Hz and face each other at distance of 1.25m. Locate the points along a line joining the two speakers where relative minima of sound pressure amplitude would be expected.

Once again, I am solving for the points where there is destructive interference. In this case, I believe that it would be the nodes. I could solve for wavelength via [itex]\frac{v}{f}[/itex] Thus wavelength equals 2.33m. Where do i go from there? How do i find the coordinates of the nodes?
 
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If you have the wavelength then you just have to find the points (P)between the speakers (S1,S2) were P(S1-S2) is a multiple of half the wavelength ((n-0.5)(wavelength/2))
 
Thank you.

Can anyone try to solve the first two problems?
 

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